A Ferris wheel is 38 meters in diameter and the bottom of the Ferris wheel is 6 meters above the ground. You board the Ferris wheel at the 3 o'clock position.

The wheel completes one full revolution every 2.2 minutes. What is the angular speed (in radians per minute) that the Ferris wheel is rotating?

2.855993
Correct radians per minute

Write a formula that gives the angle measure (in radians) swept out from the 3 o'clock position, a, in terms of the number of minutes elapsed since you boarded the Ferris wheel, t
.



Define a function f that gives your height above the ground (in meters) in terms of the number of minutes elapsed since you boarded the Ferris wheel,
t
.

1 answer

so the axle is at 38/2 + 6 = 25m up.
θ covers 2π radians every 2.2 minutes, so the angular speed is
ω = 2πrad/2.2min = π/1.1 rad/min
thus θ = π/1.1 t
Since you are rising from there, you have
h = 25 + 19sin(ωt) = 25 + 19sin(π/1.1 t)