If the lower drop has fallen 20m, its time to fall is
T = sqrt (2H/g)
where H = 20 m and g = 9.8 m/s^2
Calculate that time and then calculate how far the next drop has fallen at that time, which is
H' = (1/2)g(T - 0.25)^2
since it started to fall 0.25 seconds later than the lower drop.
The vertical drop separation at that time is H - H'
A faucet leaks at the rate of four drops each second.If air resistance is neglected, determine the vertical separation between two consecutive drops after the lower one has fallen 20m
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