A father pulls his son, whose mass is 26.7 kg and who is sitting on a swing with ropes of length 3.27 m, backward until the ropes make an angle of 35.6° with respect to the vertical. He then releases his son from rest. What is the speed of the son at the bottom of the swinging motion?

Answer 1

m g h = (1/2) m v^2
v^2 = 2 g h
v = sqrt (2 g h)

h = 3.27 (1 - cos 35.6) meters
g = 9.8 m/s^2