Let x = son's age, and y = father's age
y = 7x
y-2 = 13(x-2) = 13x - 26
Substitute 7x for y in the second equation.
7x - 2 = 13x - 26
Solve for x, then put that value into first equation. Check by putting both values into the second equation.
a father is 7times as old as his son .two years ago,the father was 13times as old as his son.how old tyey are now?
2 answers
28 year,4 year