A father distributed his entire inheritance among his four children. To the oldest he gave a third of his money; to the second, the fourth part; to the third, the fifth part, and to the youngest, the rest. What fraction of money did the fourth child get?

1 answer

Let the total amount of money the father had be represented by 1 unit.

The oldest child received 1/3 of the money, which is equal to 1/3 * 1 = 1/3.

The second child received 1/4 of the money, which is equal to 1/4 * 1 = 1/4.

The third child received 1/5 of the money, which is equal to 1/5 * 1 = 1/5.

The fourth child received the rest of the money, which is equal to 1 - 1/3 - 1/4 - 1/5 = 15/60 - 20/60 - 12/60 - 4/60 = 9/60 = 3/20.

Therefore, the fourth child received 3/20 of the money.