L w = 51
2L + 2 w = 40 so L+w=20
51/w + w = 20
w^2 - 20 w + 51 = 0
w = [ 20 +/- sqrt (400 - 204)]/2
= [ 20 +/- 14]/2
so
3 by 17
A farmer wants to set up a pigpen using 40 feet of fence to enclose a rectangular area of 51 square feet. Find the dimensions of the pigpen.
1 answer
1 answer