maybe it's time you start including some of your work in these posts. You should have some ideas by now...
2xy = 800000, so y = 400000/x
The cost
c(x) = 2y + 2(4x+2y) = 8x+6y = 8(x+300000/x)
c'(x) = 8(1-300000/x^2)
Now just find when c'=0
A farmer wants to fence a rectangular area of 800,000 m² and divide it in half with a fence that is parallel to one of the sides of the rectangle, and twice as expensive as the fence on the outer sides. How can this be done in order to minimize the cost of the fence?
Hint: If all the fencing costs the same, what are we needing to minimize in this scenario?
1 answer
3 answers