Asked by chizoba

A farmer uses an irrigation sprinkler system that pivots about the center of a circular field. Determine the length of the sprinkler if an area of 2340 square feet is watered after a pivot of 20°.

P.S: The formula is A=1/2 theta r^2
Please help me. Thank you.
Answered by Scott
Θ is in radians

20º = (2 π / 18) rad

2340 = ½ (2 π / 18) r²

18 * 2340 / π = r²
Answered by olly
12
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