4 w + 2 k = 62
w + k = 21
solve using substitution
... or elimination
A farmer raises cows and chickens. The farmer has a total of 21 animals. One day he counts the legs of all his animals and realizes he has a total of 62 legs. How many of each animal does he have?
2 answers
say that all 21 are chickens. That would give 42 legs.
Each chicken that is replaced with a cow will raise the leg count by 2.
we have 20 extra legs, so that means we need 10 cows.
Thus, 11 chickens, 10 cows
Each chicken that is replaced with a cow will raise the leg count by 2.
we have 20 extra legs, so that means we need 10 cows.
Thus, 11 chickens, 10 cows