Let L=total length of fencing.
x=width
(L/2-x)=length
A(x)=Area=x(L/2-x)
Differentiate A with respect to x, and equate A'(x) to zero and solve for x=x0 which gives the maximum or minimum area.
Differentiate A'(x) again to get A"(x).
Confirm that A"(x0) is negative for a maximum (and positive for a minimum).
You should find that x0=width=length.
Post your answer for a check if you wish.
a farmer has available 1032 feet of fencing and wishes to enclose a rectangular area. If x represents the width of the rectangle for what value of x is the area the largest
A) 256.5 feet b) 258 feet
c) 256 feet d) 257 feet
please show work!
i need help fast
3 answers
is it 258
Yes, that's correct.
0 answers