A farmer has a herd of 100 cattle with an average weight of 500 lbs/cow. It costs 50 cents a day to keep each cattle. They are gaining weight at a rate of 6 lbs per day. The market price is now $1 per lb for beef and is falling by 1 cent each day. How long should the farmer wait to sell his cattle in order to earn the most money? How much has he gained by waiting rather than selling right now?

1 answer

weight: w(t) = 500+6t
cost: c(t) = 0.50t
price: p(t) = 1.00 - 0.01t
sales profit per cow: s(t) = w(t)*p(t)-c(t)
s(t) = (500+6t)(1-t/100)- t/2

You can ignore the number of head; that's just a constant multiplier.

s(t) is just a parabola, so find the vertex for maximum profit.
Similar Questions
  1. Question 27A farmer is considering the advantages of cloning a herd of cattle from a single cow. What is one advantage of a
    1. answers icon 1 answer
    1. answers icon 2 answers
    1. answers icon 1 answer
  2. Which sentence displays correct subject-verb agreement?PLEASE HELP -The herd remain in the barn. -The herd is in the north
    1. answers icon 5 answers
more similar questions