10b + 3g + .5y = 100
b+g+y = 100
There's no unique solution, but you can see that
g = 20 - 19b/5
y = 80 + 14b/5
So, it is clear that b must be a multiple of 5. Now, if b=5,
g = 20-19b/5 = 20-19 = 1
So, 5 blue, 1 green and 94 yellows works out fine.
You can't have more than 5 blues, because then 20 - 19b/5 < 0
A farmer has 100.00 and he has to buy 100 budgies blue ones cost 10.00 green ones cost 3.00 and yellow cost .50 he has to buy at least 2 yellow and he can only spend axactly 100.00. This is a fifth grade math problem. I am a grandma trying to help my 10 year old grandson. I need help pleade.
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