You can play around with Z table stuff at
davidmlane.com/hyperstat/z_table.html
A farmer finds that the weights of sheep on his farm have a normal distribution with mean 66.4 kg
and standard deviation 5.6 kg.
250 sheep are chosen at random. Estimate the number of sheep which have a weight of between
70 kg and 72.5 kg.
5 answers
70 kg is [(70 - 66.4) / 5.6] s.d. above the mean
72.5 kg is [(72.5 - 66.4) / 5.6] s.d. above the mean
calculate the two z-scores (s.d. above the mean)
... then use a table to find the portion of the population between the scores
72.5 kg is [(72.5 - 66.4) / 5.6] s.d. above the mean
calculate the two z-scores (s.d. above the mean)
... then use a table to find the portion of the population between the scores
I need to know how to do.I tried it and got 0.13128, but the answer is 0.1221.
Do we need continuity correction also?If yes then why?
there is a z-score calculator at calculator.net
it gives greater precision than the tables
... no need for interpolation from table values
it gives greater precision than the tables
... no need for interpolation from table values