I don't understand the diamter being 8meters. It makes no sense.
Secondly, What is the exact question?
A fan at a rock concert is 45.0 m from the stage, and at this point the sound intensity level is 108 dB. Sound is detected when a sound wave causes the tympanic membrane (the eardrum) to vibrate . Typically, the diameter of this membrane is about 8.40 m in humans
I solved for the intensity using Beta = (10 dB) log I/I_0
I got I to be 3.11*10^-5 W/m^2 45m away.
Then I found the energy to be 17.22*10^-11J
The answer wants it in micro joules but I'm not even sure if I've done the problem correctly.
6 answers
oh sorry the diameter is 8.4mm
and the question is asking for the
How much energy is transferred to her eardrums each second ?
and the question is asking for the
How much energy is transferred to her eardrums each second ?
108=10 log(I/Io)
10.8=log( )
I= 10^10.8 * Io=10^10.8*1E-12=.063watts/m^2 check that.
Energy= areadrum*I= PI* .004^2*I above.
= .063watts/m^2*PI*16E-6=3.2 × 10-6 watts.
10.8=log( )
I= 10^10.8 * Io=10^10.8*1E-12=.063watts/m^2 check that.
Energy= areadrum*I= PI* .004^2*I above.
= .063watts/m^2*PI*16E-6=3.2 × 10-6 watts.
108=10 log(I/Io)
10.8=log( )
I= 10^10.8 * Io=10^10.8*1E-12=.063watts/m^2 check that.
power= areadrum*I= PI* .004^2*I above.
= .063watts/m^2*PI*16E-6=3.2 × 10-6 joules/sec
energy in one second= 3.2E-6joules
10.8=log( )
I= 10^10.8 * Io=10^10.8*1E-12=.063watts/m^2 check that.
power= areadrum*I= PI* .004^2*I above.
= .063watts/m^2*PI*16E-6=3.2 × 10-6 joules/sec
energy in one second= 3.2E-6joules
The range away from the stage doesn't matter?
the range doesnt matter because the relative intesity is already given in db
4 answers