A family is having a pool built in their backyard. If their yard is rectangular and measures 7x by 6x and the pool is circular with a radius of 2x how much of the yard will be left over after the pool is built?
A.38x2
B.42x2 – 4x2
C.42x2 – 2x2
D.38x2
I do not understand these....I have 2 problems like this...can you please explain...thank you
4 answers
If you want me to just guess I would guess A...but I still don't know how to do them...thanks
No - I would guess B....?
why guess, when you can solve it algebraically? Just take a step back and analyze the given information.
The yard has area (7x)(6x) = 42x^2
The pool has area π(2x)^2 = 4πx^2
It appears to be (B) if you include all the proper symbols
The yard has area (7x)(6x) = 42x^2
The pool has area π(2x)^2 = 4πx^2
It appears to be (B) if you include all the proper symbols
Thank you Steve...I understand now.
1 answer