If their ages are a < b < c then
c = b+8
a = c-12
a+b+c = 88
...
a family has 3 children the eldest is 8 years older than the middle child and the youngest is 12 years younger than the eldest child of the total of their age is 88 how old is each child?
2 answers
E-8=M
Y+12=E
E+Y+M=88
putting it in standard form..
E-M+0y=8
E-oM-y=12
E+M+Y=88
add the last two
2E+M=100 add to the first equation
3E=108
E=36
M=28
Y=24
Y+12=E
E+Y+M=88
putting it in standard form..
E-M+0y=8
E-oM-y=12
E+M+Y=88
add the last two
2E+M=100 add to the first equation
3E=108
E=36
M=28
Y=24