A FALSK CONTAINS 49.8 mL OF 0.150 CALCIUM HYDROXIDE. HOW MANY MILLILITERS OF 0.500 SODIUM CARBONATE ARE REQUIRED TO REACT COMPLETELY WITH THE CALCIUM HYDROXIDE IN THE FOLLOWING REACTION?

Question

A FALSK CONTAINS 49.8 mL OF 0.150 CALCIUM HYDROXIDE. HOW MANY MILLILITERS OF 0.500 SODIUM CARBONATE ARE REQUIRED TO REACT COMPLETELY WITH THE CALCIUM HYDROXIDE IN THE FOLLOWING REACTION?
Na2CO3(aq)+ Ca(OH)2(aq)¨CaCO3(s)+2NaOH(aq)

bobpursley · Answer

molesNa2CO3=molesCa(OH)2 MolarityNa2CO3(Volume)=.150*49.8ml Volulme=.150*49.8/.5 ml