molesNa2CO3=molesCa(OH)2
MolarityNa2CO3(Volume)=.150*49.8ml
Volulme=.150*49.8/.5 ml
A FALSK CONTAINS 49.8 mL OF 0.150 CALCIUM HYDROXIDE. HOW MANY MILLILITERS OF 0.500 SODIUM CARBONATE ARE REQUIRED TO REACT COMPLETELY WITH THE CALCIUM HYDROXIDE IN THE FOLLOWING REACTION?
Na2CO3(aq)+ Ca(OH)2(aq)�¨CaCO3(s)+2NaOH(aq)
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