A falling stone takes 0.320 s to pass a window 2.30 m high. From what height (in meters) above the top of the window did the stone fall?

Answer 1

Let that distance be H.

Time to reach top of window:
t1 = sqrt(2 H/g)

Time to reach bottom of window:
t2 = sqrt([2(H+2.3)/g]
t2 - t1 = 0.32 = sqrt[2(H+2.3)/g] -sqrt(2H/g)

g = 9.8 m/s^2. You have only one unknown. Solve for H

Answer 2

.789m/s^2