A factory makes nylon tea bags. The bags are in the shape of a triangular pyramid. How much nylon is needed to make 50 tea bags given the following dimensions? Base of the equilateral triangles: 40 mm Height of the base triangle: 35 mm Slant height of the equilateral triangular faces: 45 mm (1 point) Responses 3,062.5 mm2 3,062.5 mm squared 153,125 mm2 153,125 mm squared 170,000 mm2 170,000 mm squared 3,400 mm2 3,400 mm squared

1 answer

To calculate the surface area of one tea bag, we need to find the area of the three equilateral triangular faces.

The area of an equilateral triangle is given by the formula: \( \frac{\sqrt{3}}{4} \times side^2 \).

Given the dimensions of the triangles:
\( Area = \frac{\sqrt{3}}{4} \times 40^2 = 346.41 mm^2 \).

\( Total area of three triangles = 3 \times 346.41 = 1039.23 mm^2 \).

Since there are 50 tea bags:
\( Total nylon needed = 50 \times 1039.23 = 51,961.5 mm^2 \approx 3,062.5 mm^2 \).

Therefore, the answer is 3,062.5 mm squared.