y <= x+200
x+2y <= 1600
maximize 14x+22y-900
Surely (0,0) will not yield maximum profit!
If you evaluate p(x,y) at the line intersections, you will find
p(0,0) = -900
p(0,200) = 3500
p(400,600) = 17900
p(1600,0) = 21500
A factory can produce two products, x and y, with a profit approximated by P =
I think it's b but I'm not really sure. Can someone show me how to do this or let me check my answer? :)
14x + 22y – 900. The production of y can exceed x by no more than 200 units. Moreover, production levels are limited by the formula x + 2y ≤ 1600. What production levels yield maximum profit?
a. x = 400; y = 600
b. x = 0; y = 0
c. x = 1,600; y = 0
d. x = 0; y = 200
12 answers
x = 14,y = -2
x=400
y=600
y=600
Updated answers
1. D
2. D
3. A
1. D
2. D
3. A
d a d
Idiots. The answer was C [x = 1,600; y = 0], not B.
Just took the quiz they are
D
B
C
D
B
C
Sophia is right. 100%%
lil ded in here
1.D, (5,0)
2.B, 40 of type A: 80 of type B
3.C, x= 1,600; y= 0
All answers to Linear Programming.
2.B, 40 of type A: 80 of type B
3.C, x= 1,600; y= 0
All answers to Linear Programming.
Jake's 100%
Thank you Jake I got 100%