A dust particle carrying a charge of -3 x 10-10 C is 2mm to the left of another dust particle carrying a charge of +4 x 10-10C. Find the magnitude and direction of the electric force on the first particle.

Answer 1

opposite charges attract so force to the left
d = 0.002 meter
k = 9*10^9

-k Q1Q2/d^2

Answer 2

oh, sorry, did not read carefully. They want force on FIRST so equal and opposite, to the right, positive