a drunkard walking ina narrow lane takes 5 steps forward and 3 steps backward followed again 5 steps forward and 3 steps backward and so on. if each step is 1m and requires 1 second. determine how long would the drunkard take to fall in to pit 13 m away from starting point?

Answer 1

each cycle advances the drunk 2 meters
So, after 4 cycles and 4(5+3)=32 seconds, the drunk has advanced 8 meters.

The next 5 steps take him to the end, so it takes 32+5 = 37 seconds.