Another algebra problem in two variables. Why are you changing names?
Please show your work for further assistance.
A druggist mixes a 10% solution of iodine with a 15% solution of iodine. How much of each solution should be used in order to obtain 20 cubic centimeters of a 12% solution?
4 answers
I'm not changing names. This is the only one that I posted today. Because this is the only one out of my homework that I don't understand how to do.
Let X = cc of 10% iodine solution
Let Y = cc of 15% iodine solution
X + Y = 20
(0.1X + 0.15 Y) = 0.12*20
X + 1.5 Y = 24
0.5Y = 4
Take it from there.
Let Y = cc of 15% iodine solution
X + Y = 20
(0.1X + 0.15 Y) = 0.12*20
X + 1.5 Y = 24
0.5Y = 4
Take it from there.
Thanx :)