A drop of oil volume 10^-10m^3 spreads out on water to make a circular firm of radius 10^-1.what is the thickness of the firm.

Answer 1

Volume = pi^r^2*h

You know the volume and the radius from the problem Substitute and solve for h. (the thickness)

Answer 2

yes

Answer 3

Give the explanation
Of the first one

Answer 4

Please answer this question