1 mph = 5280*.3048/3600=0.44704 m/s
vi=50*.44704=22.352 m/s
vf=0
a=-10 m/s²
use kinematics equation
vf²=vi²+2aΔx
to solve for Δx.
Subtract Δx from 80m to get the distance from the wall.
a driver traveling at 50 mph is 80 m from the wall ahead. if the driver applies the brakes immediately and begins slowing the vehicle at 10 m/s squared, find the distance from the stopping point to the wall.
2 answers
25