Well, now we seem to be back in the dark ages of some king's feet.
v1 = 42*5280/3600 ft/s
v2 = 58*5280/3600 ft/s
assuming constant acceleration we can use average v
va = 50*5280/3600 ft/s
so t = 660/va
a = (v2-v1)/t
a driver traveling 42 mph speeds up to 58 mph over distance of 660 feet how long does this increase in speed take what is the driver's acceleration
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