assuming the initial velocity is nearly straight upwards...
at max height, velocity is zero
0=5-9.8t
time to max height= 5/9.8 seconds
time to water:
hf=hi+vi*t-4.8t^2
0=3+5*t-4.9t^2
solve this quadratic equation for t.
speed:
vf=5*t-9.8t^2 put in t, and you have it.
A driver jumps off the 3.0m diving board with an initial velocity of 5.0m/s. (a) Determine the maximum height, (b) The time to reach the maximum height, (c) The time it took to touch the water, and (c) The speed when touching the water.
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