A driver in a car traveling at a speed of

Question

72 km/h sees a cat 107 m away on the road.
How long will it take for the car to accelerate uniformly to a stop in exactly 104 m?

Answer 1

72 km/hr *1000/3600 = 20 m/s

average speed during acceleration = (20+0)/2 = 10 m/s

104 = 10 m/s * time to stop
so
time = t = 10.4 seconds

Answer 2

-1.923 m/s2

Answer 3

A driver in a car traveling at a speed of
73 km/h sees a cat 103 m away on the road.
How long will it take for the car to accelerate
uniformly to a stop in exactly 100 m?