Use SI units to make things easier.
Vo = 41.7 mph = 41.7*1609/3600 = 18.64 m/s
Vo = sqrt(2 a X)
X = 88 m
Solve for the reuired acceelration, a.
a = Vo^2/(2 X)= 1.97 m/s^2
A driver in a car traveling at a speed of
41.7 mi/h sees a deer 88 m away on the road.
Calculate the magnitude of the acceleration
necessary for the car to stop just barely miss-
ing the deer (assuming that the deer does not
move in the meantime).
Answer in units of m/s2
1 answer
2 answers