A doubly charged helium atom (mass = 6.68 x 10-27 kg) is accelerated through a potential difference of 3.00x 103 V. What will be the radius of curvature of the path of the atom if it is in a uniform 0.410 T magnetic field?

Answer 1

The secod part of the question is...

What is the period of revolution for the atom in the previous question?

Answer 2

Get the velocity after acceleration in the electric field, then, with that velocity..

centripetal force= magnetic force
and solve for r.