Let x = width
Let y = length
Area of rectangle is length x width, so
A = xy
912 = xy
Perimeter of rectangle is 2*(length + width), so
P = 2(x + y)
124 = 2(x + y)
62 = x + y
Now that you have two equations tow unknowns, we can solve for x and y. From the second equation, we can write an expression for y and substitute it to the first equation:
62 = x + y
y = 62 - x
912 = xy
912 = x(62 - x)
912 = 62x - x^2
Now continue solving this. Hope this helps~ `u`
A doormat has an area of 912 square inches. Its perimeter is 124 inches. What are the dimensions of the doormat?
3 answers
width ---- x
length ----y
2x + 2y = 124
x+y=62
y = 62-x
xy = 912
x(62-x) = 912
62x - x^2 - 912 = 0
x^2 - 62x + 912 = 0
(x-24)(x-38) = 0
x = 24 or x = 38, then
y = 38 or y = 24
the doormat is 24 by 38
length ----y
2x + 2y = 124
x+y=62
y = 62-x
xy = 912
x(62-x) = 912
62x - x^2 - 912 = 0
x^2 - 62x + 912 = 0
(x-24)(x-38) = 0
x = 24 or x = 38, then
y = 38 or y = 24
the doormat is 24 by 38
The perimeter of a doormat is 124 inches. It is 22 inches wide. How long is it
3 answers