A dolphin jumps with an initial velocity of 13.0at an angle of 44.0 above the horizontal. The dolphin passes through the center of a hoop before returning to the water. If the dolphin is moving horizontally when it goes through the hoop, how high above the water is the center of the hoop?

Answer 1

initial vertical velocity = Vi =13 sin 44
= 9.03 m/s (I assume you mean meters/second )

v = Vi - g t
0 = 9.03 - 9.81 t
t = .9205 second

h = (1/2) g t^2
= 4.9(.9205)^2
= 4.15 meters