Question

a dolphin jumped above the surface of the water. It reached an altitude of 3.5 m above the surface of the water and then do 10 m below the surface of the water. It went from its highest point above the water to its lowest death in 12.5 seconds, the quotient to describe the average rate of chance in the dolphins position give your answer to the nearest hundredth

Answer 1

To find the average rate of change in the dolphin's position, we first need to determine the total vertical displacement.

1. **Starting Point (Highest Point)**: The dolphin's highest point is 3.5 meters above the surface, which we can represent as +3.5 m.

2. **Ending Point (Lowest Point)**: The dolphin's lowest point is 10 meters below the surface, which we can represent as -10 m.

3. **Total Change in Position**:
\[
\text{Change in Position} = \text{Final Position} - \text{Initial Position} = (-10) - 3.5 = -13.5 \, \text{m}
\]

4. **Total Time**: The time taken for the change in position is 12.5 seconds.

5. **Average Rate of Change**:
\[
\text{Average Rate of Change} = \frac{\text{Change in Position}}{\text{Time}} = \frac{-13.5 \, \text{m}}{12.5 \, \text{s}} = -1.08 \, \text{m/s}
\]

Therefore, the average rate of change in the dolphin's position, rounded to the nearest hundredth, is \(-1.08 \, \text{m/s}\).