A dog groomer charges her clients by the weight of the dog. The following piecewise function represents the total charge, f(x)

๐‘“
(
๐‘ฅ
)
, for a dog weighing x pounds.

f(x)=โŽงโŽฉโŽจโŽชโŽช2.5x if 0โ‰คxโ‰ค203.5x if 20 <xโ‰ค50 5x if x>50
๐‘“
(
๐‘ฅ
)
=
{
2.5
๐‘ฅ

if

0
โ‰ค
๐‘ฅ
โ‰ค
20
3.5
๐‘ฅ

if

2
0

<
๐‘ฅ
โ‰ค
50

5
๐‘ฅ



if

๐‘ฅ
>
50


What would be the last point graphed on the first piece of the function, f(x)=2.5x
๐‘“
(
๐‘ฅ
)
=
2.5
๐‘ฅ
?

(1 point)
(,)

1 answer

The first piece of the function \( f(x) = 2.5x \) is defined for \( 0 \leq x \leq 20 \). The last point graphed on this piece occurs at the upper bound of the interval, which is when \( x = 20 \).

To find the corresponding \( y \) value at this point:

\[ f(20) = 2.5 \times 20 = 50 \]

Thus, the last point graphed on the first piece of the function is \( (20, 50) \).