A dodecahedral die (one with 12 sides numbered from 1 to 12) is tossed once.

Determine the number of elements in the sample space for tossing a dodecahedral die once.
n(S) =
Let E be the event that the number on the upward face is not 5. Determine the number of elements in event E.
n(E) =
Find the probability of event E. (Enter your probability as a fraction.) Show your work for all parts.

1 answer

n(S) = 12 (since there are 12 sides on the dodecahedral die)

To find n(E), we need to determine how many numbers on the die are not 5. There are 11 other numbers besides 5 on the die, so n(E) = 11.

The probability of event E occurring can be calculated as:
P(E) = n(E) / n(S) = 11 / 12

Therefore, the probability of event E is 11/12.
Similar Questions
  1. Outcomes 2 4 6 8 10 12Frequency 10 9 6 15 13 8 Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results
    1. answers icon 1 answer
  2. Outcomes 2 4 6 8 10 12Frequency 10 9 6 15 13 8 Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results
    1. answers icon 5 answers
  3. outcomes : 2, 4, 6, 8, 10, 12Frequency : 10, 9, 6, 15, 13, 8 Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12.
    1. answers icon 1 answer
    1. answers icon 3 answers
more similar questions