a diverging mirror of 52.0 focal lenght produces a virtual image of 26.0cm from the mirror.

how far from the mirror should the object be placed?

solution
f=-52.0cm, v=-26.0cm

1/u + 1/v = 1/f

rearranging the terms
1/u = 1/f - 1/v

substituting the values of v and f into the above eq. we get

1/u = 1/-52.0 - 1/-26.0

ans = 52cm

am i right pls check.

1 answer

Since it is a diverging mirror, the focal length is -52 cm, Since the image is virtual, the imaage distance is -26 cm

Do the calculation again and solve for u