Asked by Matrix School 2

a diverging mirror of 52.0 focal lenght produces a virtual image of 26.0cm from the mirror.
how far from the mirror should the object be placed?

solution
f=-52.0cm, v=-26.0cm

1/u + 1/v = 1/f

rearranging the terms
1/u = 1/f - 1/v

substituting the values of v and f into the above eq. we get

1/u = 1/-52.0 - 1/-26.0

ans = 52cm

am i right pls check.
Answered by drwls
Since it is a diverging mirror, the focal length is -52 cm, Since the image is virtual, the imaage distance is -26 cm

Do the calculation again and solve for u
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