To calculate the total potential energy (PE) of the diver before they jump, you can use the formula:
\[ PE = mgh \]
Where:
- \( m \) = mass of the diver (65 kg)
- \( g \) = acceleration due to gravity (9.8 N/kg)
- \( h \) = height above the ground (10.0 meters)
Now, substituting in the values:
\[ PE = 65 , \text{kg} \times 9.8 , \text{N/kg} \times 10.0 , \text{m} \]
Calculating this step by step:
-
Calculate \( m \times g \): \[ 65 , \text{kg} \times 9.8 , \text{N/kg} = 637 , \text{N} \]
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Now multiply by the height: \[ PE = 637 , \text{N} \times 10.0 , \text{m} = 6,370 , \text{J} \]
Thus, the total potential energy of the diver before they jump is:
\[ \text{Total Potential Energy} = 6,370 , \text{J} \]
The correct response is:
6,370 J.