A diver that weighs 65 kg stands on a high dive platform that is 10.0 meters high. Calculate the total potential energy of the diver before they jump. Use the formula PE = mgh

Hint: Remember gravity!! g = 9.8 N/kg(2 points)
Responses

6,370 J
6,370 J

66.33 J
66.33 J

84.8 J
84.8 J

63,700 J

1 answer

To calculate the total potential energy (PE) of the diver before they jump, you can use the formula:

\[ PE = mgh \]

Where:

  • \( m \) = mass of the diver (65 kg)
  • \( g \) = acceleration due to gravity (9.8 N/kg)
  • \( h \) = height above the ground (10.0 meters)

Now, substituting in the values:

\[ PE = 65 , \text{kg} \times 9.8 , \text{N/kg} \times 10.0 , \text{m} \]

Calculating this step by step:

  1. Calculate \( m \times g \): \[ 65 , \text{kg} \times 9.8 , \text{N/kg} = 637 , \text{N} \]

  2. Now multiply by the height: \[ PE = 637 , \text{N} \times 10.0 , \text{m} = 6,370 , \text{J} \]

Thus, the total potential energy of the diver before they jump is:

\[ \text{Total Potential Energy} = 6,370 , \text{J} \]

The correct response is:

6,370 J.