Question

A diver springs upward with an initial speed of 2.93 m/s from a 3.0-m board. (a) Find the velocity with which he strikes the water. [Hint: When the diver reaches the water, his displacement is y = -3.0 m (measured from the board), assuming that the downward direction is chosen as the negative direction.] (b) What is the highest point he reaches above the water?

Answer 1

at the maximum height, the PEnergy gained is equal to the initial KE

mgh=1/2 m (2.93)^2
solve for h (which is above the board).
a) for final velocity
initial PE=final KE
mg(h+3)=1/2 m vf^2
solve for vf, final velocity