Her vertical velocity component when she hits the water is
Vy' = 9.39 sin70.4
Her horizontal velocity component is
Vx = 9.39 cos70.4
The latter component remains constant during the dive.
For the initial vertical velocity component, use
Vyo^2/2 + g*2.98 m = Vy'^2/2
Use the initial horizontal and vertical velocity components, Vx and Vyo, ffor the initial velocity.
A diver springs upward from a board that is 2.98 meters above the water. At the instant she contacts the water her speed is 9.39 m/s and her body makes an angle of 70.4° with respect to the horizontal surface of the water. Determine her initial velocity.
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