To find the diver's elevation when he is \( \frac{2}{3} \) of the way down to a depth of 97.2 feet, we first need to calculate \( \frac{2}{3} \) of 97.2 feet:
\[ \frac{2}{3} \times 97.2 = \frac{194.4}{3} = 64.8 \text{ feet} \]
Now, we subtract this distance from the total depth to find the diver's elevation:
\[ 97.2 - 64.8 = 32.4 \text{ feet} \]
Since the diver is below the surface, we express this as a negative elevation:
\[ -\text{32.4} \text{ ft.} \]
So, the diver's elevation when he is \( \frac{2}{3} \) of the way down is
\(-32.4\) ft.