A diver searches for a sunken treasure that is 97.2

feet below the surface. What is the diver's elevation when he is 2/3 of the way down? (1 point)
Responses

−48.5
ft.
negative 48 point 5 ft.

−145.8 ft.
negative 145 point 8 ft.

−64.8
ft.
negative 64 point 8 ft.

−32.4
ft.

1 answer

To find the diver's elevation when he is \( \frac{2}{3} \) of the way down to a depth of 97.2 feet, we first need to calculate \( \frac{2}{3} \) of 97.2 feet:

\[ \frac{2}{3} \times 97.2 = \frac{194.4}{3} = 64.8 \text{ feet} \]

Now, we subtract this distance from the total depth to find the diver's elevation:

\[ 97.2 - 64.8 = 32.4 \text{ feet} \]

Since the diver is below the surface, we express this as a negative elevation:

\[ -\text{32.4} \text{ ft.} \]

So, the diver's elevation when he is \( \frac{2}{3} \) of the way down is

\(-32.4\) ft.