a ball 1 is thrown horizontally from the top of a building that is 50 meters tall. if another ball 2 is dropped at the same time as the first is released, which ball will hit the ground first?
A. ball 1
B. ball 2
c. they land at the same
D. depends of the initial velocity of ball 1
A diver runs horizontally with a speed of 1.5 m/s off a platform that is 20 m above the water. what is his speed just before hitting the ground?
6 answers
These two questions are really the same.
in the first the horizontal velocity remains 1.5 the whole time
then vertical problem
20 = 4.9 t^2
solve for t
Thern use that t to get v, speed down at ground
v = g t
v = 9.81 t
then
speed = sqrt (2.25 + v^2)
The second problem is trivial. The horizontal problem has nothing to do with the vertical problem. They fall at the same rate.
in the first the horizontal velocity remains 1.5 the whole time
then vertical problem
20 = 4.9 t^2
solve for t
Thern use that t to get v, speed down at ground
v = g t
v = 9.81 t
then
speed = sqrt (2.25 + v^2)
The second problem is trivial. The horizontal problem has nothing to do with the vertical problem. They fall at the same rate.
I still need help ebcause the answers are
A. 2.5 m/s
B. 5 m/s
C. 1.75 m/s
D. 2 m/s
NOT 19 M/S
A. 2.5 m/s
B. 5 m/s
C. 1.75 m/s
D. 2 m/s
NOT 19 M/S
A ball rolls off a 1 meters high desk and hits the ground 5 m away from the bottom of the desk. Determine the initial velocity of the ball. Free response
Your problems are all the same.
range = u t
t is time to fall one meter
h = (1/2) g t^2
so
t = sqrt (2 g h) remember that
so
t = sqrt (2*9.81*1)
then
5 meters = u t and we know t
so solve for u
range = u t
t is time to fall one meter
h = (1/2) g t^2
so
t = sqrt (2 g h) remember that
so
t = sqrt (2*9.81*1)
then
5 meters = u t and we know t
so solve for u
u=5 meters?
1 answer