A diver of mass m drops from a board 12 m above the water surface. Calculate his speed 6m above the water surface. What is the speed of the diver just he strikes the water?

Answer 1

V^2 = Vo + 2g*d
V^2 = 0 + 19.6*(12-6) = 117.6
V = 10.84 m/s.

V^2 = 0 + 19.6*12 = 235.2
V = 15.34 m/s