A diver leaves a 3m board on a trajectory that takes her 2.5m above the board and then into the water a horizontal distance of 2.9m from the end of the board. At what speed did she leave the board? At what angle did she leave the board?

Answer 1

The speed at which the diver left the board can be calculated using the equation:

Speed = √(2 * g * height)

where g is the acceleration due to gravity (9.8 m/s2).

Therefore, the speed at which the diver left the board is:

Speed = √(2 * 9.8 * 3) = 10.8 m/s

The angle at which the diver left the board can be calculated using the equation:

Angle = arctan(horizontal distance / height)

Therefore, the angle at which the diver left the board is:

Angle = arctan(2.9 / 2.5) = 63.4°