To find the x-intercept of the function \( h(t) = -16t^2 + 20t \), we need to set \( h(t) \) equal to zero and solve for \( t \):
\[ -16t^2 + 20t = 0 \]
We can factor out \( t \) from the equation:
\[ t(-16t + 20) = 0 \]
This gives us two solutions:
- \( t = 0 \) (the time when the diver just jumped off the platform)
- \( -16t + 20 = 0 \)
Now solve for \( t \) in the second part:
\[ -16t + 20 = 0 \]
\[ -16t = -20 \]
\[ t = \frac{20}{16} = \frac{5}{4} = 1.25 \text{ seconds} \]
Thus, the x-intercepts are \( t = 0 \) and \( t = 1.25 \).
Interpretation of Meaning:
The x-intercepts represent the times at which the height of the diver \( h(t) \) is 0, meaning the diver is at the water's surface.
- At \( t = 0 \) seconds, the diver is just about to jump from the platform.
- At \( t = 1.25 \) seconds, the diver hits the water after jumping off the platform.
In summary, the diver enters the water again after 1.25 seconds.