10 + 2t - 4.9t² = 0
t = 1.647 s
b) take the derivative and plug in 1.647 s
dh/dt = 2 - 9.8 t
dh/dt = 2 - 9.8 (1.647 ) = -14.14 m/s
A diver is on the 10 m platform, preparing to perform a dive. The diver’s height above the water, in metres, at time t can be modelled using the equation
h(t)= 10+ 2t - 4.9t^2.
a) Determine when the diver will enter the water.
b) Estimate the rate at which the diver’s height above the water is
changing as the diver enters the water.
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