A distribution of values is normal with a mean of 65.2 and a standard deviation of 7.4.

Find P32, which is the score separating the bottom 32% from the top 68%.
P32 =

Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

2 answers

http://davidmlane.com/hyperstat/z_table.html
How to do this on your own.

Look in the back of your statistics textbook for a table called something like “area under normal distribution” to find the proportion/probability (P=.32) and its Z score.

Z = (score-mean)/SD

Insert data to solve.