F = ma, and in rotational
Tau = I alpha
so alpha = .2/.04
then use eq of motion
theta = 1/2 alpha t^2
A disk is free to rotate around its fixed axis of revolution (delta). The moment of inertia of disk around delta is J=4×10^-2 kg.m^2
This disk is initially at rest is submitted to the action of a couple whose moment is equal to 0.2 N.m
What's the number of revolutions the disk performs during the first 2 seconds of motion
1 answer
1 answer