Let's assume the cost of one small table is x dollars and the cost of one chair is y dollars.
From the first statement, we can form the equation:
5x + 8y = 115 --------(1)
From the second statement, we can form the equation:
3x + 5y = 70 -----------(2)
To solve this system of equations, we can use the method of substitution or elimination.
Using the method of elimination, let's multiply equation (2) by 2, to make the coefficients of x in both equations the same:
6x + 10y = 140 --------(3)
Now, subtract equation (1) from equation (3):
(6x + 10y) - (5x + 8y) = 140 - 115
x + 2y = 25 -----------(4)
Now, let's multiply equation (4) by 5 and subtract it from equation (1):
5x + 8y - (5(x + 2y) = 115 - 5(25)
5x + 8y - 5x - 10y = 115 - 125
-2y = -10
Divide both sides of the equation by -2:
y = -10 / -2
y = 5
Now substitute the value of y into equation (4):
x + 2(5) = 25
x + 10 = 25
x = 25 - 10
x = 15
Therefore, the cost of one small table is $15 and the cost of one chair is $5.
Answer: A: x = $15; y = $5
A discount store is selling 5 small tables with 8 chairs for $115. Three tables with 5 chairs cost $70.
A: x = $15; y = $5
B: x = $10; y = $5
C: x = $5; y = $10
D: x = $12; y = $3
1 answer
1 answer