A disc without slipping rolls down a hill height 10.0 m. If the disc starts from rest at the top of hill, what is its speed at the bottom?

Answer 1

final KE=initial PE
where initial PE=mgh=mass*9.8*10
final KE = rolling KE + translational KE
= 1/2(I)w^2 + 1/2 m v^2= 1/2 (Mr^2)(v^2/r) + 1/2 M v^2
put all in this equation
final KE=initial PE
and solve for veloicy v.

Answer 2

A disc without slipping rolls down a hill of height 10m. If the disc starts form rest at the top of the hill, its speed at the bottom is:

Answer 3

= 1/2(I)w^2 + 1/2 m v^2= 1/2 (Mr^2)(v^2/r) + 1/2 M v^2

Answer 4

Chal.chal

Answer 5

Sir ma Dard na karo Ziyda Phaar karr

Answer 6

Sukoon karo Koi bissness karo