A dilation with a scale factor of 12 is applied to the three line segments shown. The resulting images are A′B′¯¯¯¯¯¯¯, ​D′E′¯¯¯¯¯¯¯​ , and R′S′¯¯¯¯¯¯¯.

1 answer

To find the images of the line segments after the dilation with a scale factor of 12, we need to multiply the lengths of the original line segments by 12.

Let's say the lengths of the original line segments are:

AB = 3 units
DE = 5 units
RS = 7 units

After applying the dilation with a scale factor of 12, the new lengths of the line segments will be:

A'B' = 3 * 12 = 36 units
D'E' = 5 * 12 = 60 units
R'S' = 7 * 12 = 84 units

Therefore, the lengths of the new line segments are:

A'B' = 36 units
D'E' = 60 units
R'S' = 84 units

These are the resulting images of the line segments after the dilation with a scale factor of 12.